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Using a standard conversion factor: 100 gallons of liquid propane
converts to 378.5 liters of liquid propane
Therefore 378.5 liters of liquid propane
(x 270) will expand to 102195.0 liters when vaporized. 1.0 ml = 1.0
cm3 and 1,000,000 cm3 = 1 m3.
Therefore, 1,000,000 ml = 1 m3
also 1,000,000 ml = 1000 liters.
Therefore, 1000 liters = 1 m3.
Converting total liters to cubic meters
102195.0 liters / 1000 l/ m3
= 102.2 m3 vaporous propane = 100 gallons liquid propane
originally. A ratio of 1:1
Finally, calculating the “run time". for a 100 gallon tank
with a generator running at 75% load consuming 1.5 m3/hr
of propane.
Restated in formula format.
A 100 gallon tank (containing 102.2
m3 vaporous propane), burned at 1.5 m3/hr.
(rated 75% capacity) = 68 hrs. or 2.8 days
If you use the 80% rule then that converts to 80 % of 2.8 or 2.27
days or 54.48 hours.
This can be restated in a formula as follows:
FORMULA ANSWER:
Tank Size in Gallons
X .81756
/
Fuel Consumption in
m3/hr =
generator running hours on this tank.
ENGLISH LANGUAGE DESCRIPTION OF THE FORMULA:
Take propane Tank Size (in Gallons)
and multiply times
.81756, this number is
divided by Fuel
Consumption (in cubic meters per hour)
Equals hours of running time in hours for this tank.
If you require days, divide by 24.
Examples:
For a
100 gallon tank
burned at a rate of
1.5
m3/hr,
the estimated
run time
would equal
2.27 days
For a
150 gallon tank
burned at a rate of
1.5
m3/hr,
the estimated
run time
would equal
3.41 days
For a
200 gallon tank
burned at a rate of
1.5
m3/hr,
the estimated
run time
would equal
4.54 days
For a
100 gallon tank
burned
at a
rate of 1.1
m3/hr,
the estimated
run time
would equal
3.10 days
For a
100 gallon tank
burned
at
a rate of
1.3
m3/hr,
the estimated
run time
would equal
2.62 days
For a
100 gallon tank
burned at a
rate of
1.9
m3/hr,
the estimated
run time
would equal
1.79 days
For a
200 gallon tank
burned at a
rate of
1.7
m3/hr,
the estimated
run time
would equal
4.01 days |